Номер 13, страница 5 - гдз по алгебре 10 класс учебник Абылкасымова, Жумагулова

Алгебра, 10 класс Учебник, авторы: Абылкасымова Алма Есимбековна, Жумагулова Зауре Абдыкеновна, издательство Мектеп, Алматы, 2019

Авторы: Абылкасымова А. Е., Жумагулова З. А.

Тип: Учебник

Издательство: Мектеп

Год издания: 2019 - 2026

ISBN: 978-601-07-1142-6

Утверждено Министерством образования и науки Республики Казахстан

Упражнения для повторения курса алгебры 7—9 классов - номер 13, страница 5.

App\Models\Task {#1030 // resources/views/models/task/default.blade.php
  #connection: "mysql"
  #table: "tasks"
  #primaryKey: "id"
  #keyType: "int"
  +incrementing: true
  #with: []
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  #perPage: 15
  +exists: true
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  #escapeWhenCastingToString: false
  #attributes: array:24 [
    "id" => 1113603
    "created_at" => "2026-04-10 13:58:26"
    "updated_at" => null
    "field_page_start" => "5"
    "field_page_end" => "6"
    "field_url" => "/10-klass/algebra/abylkasymova-uchebnik/00-13"
    "field_display_title" => "13"
    "field_outside_task" => "0"
    "field_task_type" => Illuminate\Database\Eloquent\Collection {#1037
      #items: array:1 [
        0 => App\Models\Term {#1036
          #connection: "mysql"
          #table: "terms"
          #primaryKey: "id"
          #keyType: "int"
          +incrementing: false
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          #attributes: array:6 [
            "id" => 26
            "created_at" => "2026-04-10 13:58:26"
            "updated_at" => null
            "name" => "номер"
            "field_cases" => array:6 [
              "field_accusative_case" => "номер"
              "field_creative_case" => "номером"
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              "field_genitive_case" => "номера"
              "field_nominative_case" => "номер"
              "field_prepositional_case" => "номере"
            ]
            "field_short_name" => ""
          ]
          #original: array:6 [
            "id" => 26
            "created_at" => "2026-04-10 13:58:26"
            "updated_at" => null
            "name" => "номер"
            "field_cases" => array:6 [
              "field_accusative_case" => "номер"
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              "field_nominative_case" => "номер"
              "field_prepositional_case" => "номере"
            ]
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          ]
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            0 => "*"
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    }
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    "field_description_bottom" => null
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    "breadcrumbs" => []
    "edition_groups" => Illuminate\Database\Eloquent\Collection {#1035
      #items: []
      #escapeWhenCastingToString: false
    }
    "top_parent_branch" => Illuminate\Database\Eloquent\Collection {#1046
      #items: array:1 [
        0 => App\Models\Branch {#1045
          #connection: "mysql"
          #table: "branches"
          #primaryKey: "id"
          #keyType: "int"
          +incrementing: true
          #with: []
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          #attributes: array:24 [
            "id" => 1113551
            "created_at" => "2026-04-10 13:58:26"
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            "field_display_title" => "Упражнения для повторения курса алгебры 7—9 классов"
            "field_branch_order" => null
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            "field_branch_type" => Illuminate\Database\Eloquent\Collection {#1047
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            "field_branch_covers" => []
            "book" => Illuminate\Database\Eloquent\Collection {#1077
              #items: array:1 [
                0 => App\Models\Book {#1048
                  #connection: "mysql"
                  #table: "books"
                  #primaryKey: "id"
                  #keyType: "int"
                  +incrementing: false
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                  #attributes: array:50 [
                    "id" => 4293
                    "created_at" => "2026-04-10 13:58:26"
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                    "field_subject" => Illuminate\Database\Eloquent\Collection {#1050
                      #items: array:1 [
                        0 => App\Models\Term {#1049
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                          #attributes: array:10 [
                            "id" => 6471
                            "created_at" => "2026-04-10 13:58:26"
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                            ]
                            "field_foreign_lang_name" => null
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                            "field_subject_type" => "technical_subject"
                            "field_translit" => "algebra"
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                            "id" => 6471
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                            ]
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                          #hidden: []
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                            0 => "*"
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                        }
                      ]
                      #escapeWhenCastingToString: false
                    }
                    "field_class" => Illuminate\Database\Eloquent\Collection {#1051
                      #items: array:1 [
                        0 => App\Models\Term {#1052
                          #connection: "mysql"
                          #table: "terms"
                          #primaryKey: "id"
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                          #with: []
                          #withCount: []
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                          +exists: true
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                          #escapeWhenCastingToString: false
                          #attributes: array:6 [
                            "id" => 5459
                            "created_at" => "2026-04-10 13:58:26"
                            "updated_at" => null
                            "name" => "10"
                            "field_cases" => array:6 [
                              "field_accusative_case" => "десятый"
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                              "field_dative_case" => "десятому"
                              "field_genitive_case" => "десятого"
                              "field_nominative_case" => "десятый"
                              "field_prepositional_case" => "десятом"
                            ]
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                          ]
                          #original: array:6 [
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                            "updated_at" => null
                            "name" => "10"
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                              "field_nominative_case" => "десятый"
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                    "field_publisher" => Illuminate\Database\Eloquent\Collection {#1053
                      #items: array:1 [
                        0 => App\Models\Term {#1054
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                            "created_at" => "2026-04-10 13:58:26"
                            "updated_at" => null
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                          #original: array:6 [
                            "id" => 6996
                            "created_at" => "2026-04-10 13:58:26"
                            "updated_at" => null
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                            "field_translit" => "mektep"
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                          #changes: []
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                      #escapeWhenCastingToString: false
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                    "field_author" => Illuminate\Database\Eloquent\Collection {#1055
                      #items: array:2 [
                        0 => App\Models\Term {#1056
                          #connection: "mysql"
                          #table: "terms"
                          #primaryKey: "id"
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                            "created_at" => "2026-04-10 13:58:26"
                            "updated_at" => null
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                        1 => App\Models\Term {#1057
                          #connection: "mysql"
                          #table: "terms"
                          #primaryKey: "id"
                          #keyType: "int"
                          +incrementing: false
                          #with: []
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                            "created_at" => "2026-04-10 13:58:26"
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                            "field_bio" => null
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                            "field_name" => "Зауре"
                            "field_patronymic" => "Абдыкеновна"
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                      #items: array:1 [
                        0 => App\Models\Term {#1060
                          #connection: "mysql"
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                            "created_at" => "2026-04-10 13:58:26"
                            "updated_at" => null
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            "text" => "<p><strong>а)</strong> Пусть первое натуральное число равно $x$, а второе натуральное число равно $y$.</p><p>Из условия задачи известно, что первое число составляет 75% от второго, что можно записать в виде уравнения:$x = 0.75y$ или $x = \frac{3}{4}y$.</p><p>Также известно, что произведение этих чисел равно 1200:$x \cdot y = 1200$.</p><p>Подставим первое уравнение во второе:$(\frac{3}{4}y) \cdot y = 1200$</p><p>$\frac{3}{4}y^2 = 1200$</p><p>$y^2 = \frac{1200 \cdot 4}{3}$</p><p>$y^2 = 400 \cdot 4$</p><p>$y^2 = 1600$</p><p>Так как $y$ — натуральное число, $y = \sqrt{1600} = 40$.</p><p>Теперь найдем $x$, подставив значение $y$ в первое уравнение:$x = \frac{3}{4} \cdot 40 = 3 \cdot 10 = 30$.</p><p>Искомые натуральные числа — 30 и 40.Проверка: $30 \cdot 40 = 1200$. $30 / 40 = 0.75 = 75\%$.</p><p><strong>Ответ:</strong> 30 и 40.</p><p><strong>б)</strong> Пусть первоначальная дробь равна $\frac{x}{y}$.</p><p>Если числитель увеличить на 2, а знаменатель на 3, получим новую дробь $\frac{x+2}{y+3}$.</p><p>В условии сказано, что новая дробь на $\frac{49}{35}$ больше данной. Запишем уравнение:$\frac{x+2}{y+3} = \frac{x}{y} + \frac{49}{35}$.</p><p>Упростим дробь $\frac{49}{35} = \frac{7}{5}$.$\frac{x+2}{y+3} = \frac{x}{y} + \frac{7}{5}$.</p><p>Преобразуем уравнение:$\frac{x+2}{y+3} - \frac{x}{y} = \frac{7}{5}$</p><p>$\frac{y(x+2) - x(y+3)}{y(y+3)} = \frac{7}{5}$</p><p>$\frac{xy+2y-xy-3x}{y^2+3y} = \frac{7}{5}$</p><p>$\frac{2y-3x}{y^2+3y} = \frac{7}{5}$</p><p>$5(2y-3x) = 7(y^2+3y)$</p><p>$10y - 15x = 7y^2 + 21y$</p><p>$7y^2 + 11y + 15x = 0$</p><p>Для натуральных (положительных) чисел $x$ и $y$ сумма $7y^2 + 11y + 15x$ всегда будет положительной и не может равняться нулю. Это означает, что в условии задачи, скорее всего, опечатка. Наиболее вероятная опечатка — в значении $\frac{49}{35}$. Предположим, что имелось в виду $\frac{4}{35}$.</p><p>Тогда уравнение примет вид:$\frac{2y-3x}{y^2+3y} = \frac{4}{35}$</p><p>$35(2y-3x) = 4(y^2+3y)$</p><p>$70y - 105x = 4y^2 + 12y$</p><p>$105x = 58y - 4y^2$</p><p>$105x = 2y(29-2y)$</p><p>Поскольку $x$ и $y$ должны быть натуральными числами, $x &gt; 0$, следовательно $29-2y &gt; 0$, что означает $2y &lt; 29$ или $y \le 14$.</p><p>Правая часть $2y(29-2y)$ должна быть делимой на 105, то есть на 3, 5 и 7.Проверим возможные значения $y$ от 1 до 14.Если $y=7$:$105x = 2 \cdot 7 \cdot (29 - 2 \cdot 7) = 14 \cdot (29 - 14) = 14 \cdot 15 = 210$.</p><p>$x = \frac{210}{105} = 2$.</p><p>Получили натуральные $x=2$ и $y=7$. Первоначальная дробь — $\frac{2}{7}$.</p><p>Проверка: новая дробь $\frac{2+2}{7+3} = \frac{4}{10} = \frac{2}{5}$. Разность $\frac{2}{5} - \frac{2}{7} = \frac{14-10}{35} = \frac{4}{35}$. Условие выполнено.</p><p><strong>Ответ:</strong> $\frac{2}{7}$.</p><p><strong>в)</strong> Пусть двузначное число состоит из цифры десятков $a$ и цифры единиц $b$. Значение числа равно $10a+b$.Из условия задачи имеем систему уравнений:1. Сумма цифр равна 9: $a+b=9$.2. Разность квадратов цифр равна 27: $a^2-b^2=27$. (Так как разность положительна, квадрат цифры десятков больше квадрата цифры единиц, $a &gt; b$).</p><p>Разложим второе уравнение по формуле разности квадратов:$(a-b)(a+b)=27$.</p><p>Подставим в это уравнение значение $a+b$ из первого уравнения:$(a-b) \cdot 9 = 27$.</p><p>$a-b = \frac{27}{9} = 3$.</p><p>Теперь у нас есть простая система из двух линейных уравнений:$\begin{cases} a+b=9 \\ a-b=3 \end{cases}$</p><p>Сложим два уравнения:$(a+b)+(a-b) = 9+3$</p><p>$2a = 12$</p><p>$a = 6$.</p><p>Подставим значение $a$ в первое уравнение:$6+b=9$</p><p>$b=3$.</p><p>Цифра десятков равна 6, цифра единиц равна 3. Искомое число — 63.</p><p><strong>Ответ:</strong> 63.</p><p><strong>г)</strong> Пусть $v_c$ — собственная скорость катера в км/ч. Скорость течения реки $v_p = 3$ км/ч.</p><p>Скорость катера по течению: $v_{по} = v_c + v_p = v_c + 3$ км/ч.</p><p>Скорость катера против течения: $v_{против} = v_c - v_p = v_c - 3$ км/ч. (При этом $v_c &gt; 3$).</p><p>Время движения по течению: $t_{по} = \frac{S_{по}}{v_{по}} = \frac{36}{v_c+3}$ ч.</p><p>Время движения против течения: $t_{против} = \frac{S_{против}}{v_{против}} = \frac{48}{v_c-3}$ ч.</p><p>Общее время в пути составляет 6 часов:$t_{по} + t_{против} = 6$</p><p>$\frac{36}{v_c+3} + \frac{48}{v_c-3} = 6$.</p><p>Разделим все уравнение на 6 для упрощения:$\frac{6}{v_c+3} + \frac{8}{v_c-3} = 1$.</p><p>Приведем к общему знаменателю $(v_c+3)(v_c-3)$:$6(v_c-3) + 8(v_c+3) = (v_c+3)(v_c-3)$</p><p>$6v_c - 18 + 8v_c + 24 = v_c^2 - 9$</p><p>$14v_c + 6 = v_c^2 - 9$</p><p>$v_c^2 - 14v_c - 15 = 0$.</p><p>Решим квадратное уравнение. Дискриминант $D = b^2 - 4ac = (-14)^2 - 4 \cdot 1 \cdot (-15) = 196 + 60 = 256$.</p><p>$v_c = \frac{-b \pm \sqrt{D}}{2a} = \frac{14 \pm \sqrt{256}}{2} = \frac{14 \pm 16}{2}$.</p><p>Получаем два корня:$v_{c1} = \frac{14+16}{2} = \frac{30}{2} = 15$.$v_{c2} = \frac{14-16}{2} = \frac{-2}{2} = -1$.</p><p>Скорость не может быть отрицательной, поэтому $v_c = 15$ км/ч. Это значение удовлетворяет условию $v_c &gt; 3$.</p><p><strong>Ответ:</strong> 15 км/ч.</p><p><strong>д)</strong> Пусть $v_1$ — скорость первого поезда (в км/ч), а $v_2$ — скорость второго поезда (в км/ч).</p><p>Из первого условия: время первого поезда для прохождения 180 км ($t_1 = \frac{180}{v_1}$) на 1,5 часа меньше времени второго ($t_2 = \frac{180}{v_2}$):$\frac{180}{v_2} - \frac{180}{v_1} = 1.5$.</p><p>Из второго условия: вместе за 3 часа поезда проезжают 162 км. Это означает, что сумма их скоростей, умноженная на 3, равна 162:$3(v_1 + v_2) = 162$.</p><p>Из второго уравнения находим сумму скоростей:$v_1 + v_2 = \frac{162}{3} = 54$.</p><p>Отсюда $v_1 = 54 - v_2$.</p><p>Подставим это выражение в первое уравнение:$\frac{180}{v_2} - \frac{180}{54 - v_2} = 1.5$.</p><p>Разделим уравнение на 1.5 (или умножим на 2/3):$\frac{120}{v_2} - \frac{120}{54 - v_2} = 1$.</p><p>Приведем к общему знаменателю $v_2(54-v_2)$:$120(54 - v_2) - 120v_2 = v_2(54 - v_2)$</p><p>$6480 - 120v_2 - 120v_2 = 54v_2 - v_2^2$</p><p>$6480 - 240v_2 = 54v_2 - v_2^2$</p><p>$v_2^2 - 294v_2 + 6480 = 0$.</p><p>Решим квадратное уравнение. Дискриминант $D = b^2 - 4ac = (-294)^2 - 4 \cdot 1 \cdot 6480 = 86436 - 25920 = 60516$.</p><p>$\sqrt{D} = \sqrt{60516} = 246$.</p><p>$v_2 = \frac{294 \pm 246}{2}$.</p><p>Получаем два корня для $v_2$:$v_{2_a} = \frac{294+246}{2} = \frac{540}{2} = 270$.$v_{2_b} = \frac{294-246}{2} = \frac{48}{2} = 24$.</p><p>Рассмотрим оба случая:1. Если $v_2 = 270$ км/ч, то $v_1 = 54 - 270 = -216$ км/ч. Скорость не может быть отрицательной, этот корень не подходит.2. Если $v_2 = 24$ км/ч, то $v_1 = 54 - 24 = 30$ км/ч. Оба значения положительны и являются решением.</p><p>Проверка: $t_1 = 180/30 = 6$ ч. $t_2 = 180/24 = 7.5$ ч. $t_2 - t_1 = 7.5 - 6 = 1.5$ ч. Условие выполняется.</p><p><strong>Ответ:</strong> скорость первого поезда 30 км/ч, скорость второго поезда 24 км/ч.</p>"
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            "text" => "<p><strong>а)</strong> Пусть первое натуральное число равно $x$, а второе натуральное число равно $y$.</p><p>Из условия задачи известно, что первое число составляет 75% от второго, что можно записать в виде уравнения:$x = 0.75y$ или $x = \frac{3}{4}y$.</p><p>Также известно, что произведение этих чисел равно 1200:$x \cdot y = 1200$.</p><p>Подставим первое уравнение во второе:$(\frac{3}{4}y) \cdot y = 1200$</p><p>$\frac{3}{4}y^2 = 1200$</p><p>$y^2 = \frac{1200 \cdot 4}{3}$</p><p>$y^2 = 400 \cdot 4$</p><p>$y^2 = 1600$</p><p>Так как $y$ — натуральное число, $y = \sqrt{1600} = 40$.</p><p>Теперь найдем $x$, подставив значение $y$ в первое уравнение:$x = \frac{3}{4} \cdot 40 = 3 \cdot 10 = 30$.</p><p>Искомые натуральные числа — 30 и 40.Проверка: $30 \cdot 40 = 1200$. $30 / 40 = 0.75 = 75\%$.</p><p><strong>Ответ:</strong> 30 и 40.</p><p><strong>б)</strong> Пусть первоначальная дробь равна $\frac{x}{y}$.</p><p>Если числитель увеличить на 2, а знаменатель на 3, получим новую дробь $\frac{x+2}{y+3}$.</p><p>В условии сказано, что новая дробь на $\frac{49}{35}$ больше данной. Запишем уравнение:$\frac{x+2}{y+3} = \frac{x}{y} + \frac{49}{35}$.</p><p>Упростим дробь $\frac{49}{35} = \frac{7}{5}$.$\frac{x+2}{y+3} = \frac{x}{y} + \frac{7}{5}$.</p><p>Преобразуем уравнение:$\frac{x+2}{y+3} - \frac{x}{y} = \frac{7}{5}$</p><p>$\frac{y(x+2) - x(y+3)}{y(y+3)} = \frac{7}{5}$</p><p>$\frac{xy+2y-xy-3x}{y^2+3y} = \frac{7}{5}$</p><p>$\frac{2y-3x}{y^2+3y} = \frac{7}{5}$</p><p>$5(2y-3x) = 7(y^2+3y)$</p><p>$10y - 15x = 7y^2 + 21y$</p><p>$7y^2 + 11y + 15x = 0$</p><p>Для натуральных (положительных) чисел $x$ и $y$ сумма $7y^2 + 11y + 15x$ всегда будет положительной и не может равняться нулю. Это означает, что в условии задачи, скорее всего, опечатка. Наиболее вероятная опечатка — в значении $\frac{49}{35}$. Предположим, что имелось в виду $\frac{4}{35}$.</p><p>Тогда уравнение примет вид:$\frac{2y-3x}{y^2+3y} = \frac{4}{35}$</p><p>$35(2y-3x) = 4(y^2+3y)$</p><p>$70y - 105x = 4y^2 + 12y$</p><p>$105x = 58y - 4y^2$</p><p>$105x = 2y(29-2y)$</p><p>Поскольку $x$ и $y$ должны быть натуральными числами, $x &gt; 0$, следовательно $29-2y &gt; 0$, что означает $2y &lt; 29$ или $y \le 14$.</p><p>Правая часть $2y(29-2y)$ должна быть делимой на 105, то есть на 3, 5 и 7.Проверим возможные значения $y$ от 1 до 14.Если $y=7$:$105x = 2 \cdot 7 \cdot (29 - 2 \cdot 7) = 14 \cdot (29 - 14) = 14 \cdot 15 = 210$.</p><p>$x = \frac{210}{105} = 2$.</p><p>Получили натуральные $x=2$ и $y=7$. Первоначальная дробь — $\frac{2}{7}$.</p><p>Проверка: новая дробь $\frac{2+2}{7+3} = \frac{4}{10} = \frac{2}{5}$. Разность $\frac{2}{5} - \frac{2}{7} = \frac{14-10}{35} = \frac{4}{35}$. Условие выполнено.</p><p><strong>Ответ:</strong> $\frac{2}{7}$.</p><p><strong>в)</strong> Пусть двузначное число состоит из цифры десятков $a$ и цифры единиц $b$. Значение числа равно $10a+b$.Из условия задачи имеем систему уравнений:1. Сумма цифр равна 9: $a+b=9$.2. Разность квадратов цифр равна 27: $a^2-b^2=27$. (Так как разность положительна, квадрат цифры десятков больше квадрата цифры единиц, $a &gt; b$).</p><p>Разложим второе уравнение по формуле разности квадратов:$(a-b)(a+b)=27$.</p><p>Подставим в это уравнение значение $a+b$ из первого уравнения:$(a-b) \cdot 9 = 27$.</p><p>$a-b = \frac{27}{9} = 3$.</p><p>Теперь у нас есть простая система из двух линейных уравнений:$\begin{cases} a+b=9 \\ a-b=3 \end{cases}$</p><p>Сложим два уравнения:$(a+b)+(a-b) = 9+3$</p><p>$2a = 12$</p><p>$a = 6$.</p><p>Подставим значение $a$ в первое уравнение:$6+b=9$</p><p>$b=3$.</p><p>Цифра десятков равна 6, цифра единиц равна 3. Искомое число — 63.</p><p><strong>Ответ:</strong> 63.</p><p><strong>г)</strong> Пусть $v_c$ — собственная скорость катера в км/ч. Скорость течения реки $v_p = 3$ км/ч.</p><p>Скорость катера по течению: $v_{по} = v_c + v_p = v_c + 3$ км/ч.</p><p>Скорость катера против течения: $v_{против} = v_c - v_p = v_c - 3$ км/ч. (При этом $v_c &gt; 3$).</p><p>Время движения по течению: $t_{по} = \frac{S_{по}}{v_{по}} = \frac{36}{v_c+3}$ ч.</p><p>Время движения против течения: $t_{против} = \frac{S_{против}}{v_{против}} = \frac{48}{v_c-3}$ ч.</p><p>Общее время в пути составляет 6 часов:$t_{по} + t_{против} = 6$</p><p>$\frac{36}{v_c+3} + \frac{48}{v_c-3} = 6$.</p><p>Разделим все уравнение на 6 для упрощения:$\frac{6}{v_c+3} + \frac{8}{v_c-3} = 1$.</p><p>Приведем к общему знаменателю $(v_c+3)(v_c-3)$:$6(v_c-3) + 8(v_c+3) = (v_c+3)(v_c-3)$</p><p>$6v_c - 18 + 8v_c + 24 = v_c^2 - 9$</p><p>$14v_c + 6 = v_c^2 - 9$</p><p>$v_c^2 - 14v_c - 15 = 0$.</p><p>Решим квадратное уравнение. Дискриминант $D = b^2 - 4ac = (-14)^2 - 4 \cdot 1 \cdot (-15) = 196 + 60 = 256$.</p><p>$v_c = \frac{-b \pm \sqrt{D}}{2a} = \frac{14 \pm \sqrt{256}}{2} = \frac{14 \pm 16}{2}$.</p><p>Получаем два корня:$v_{c1} = \frac{14+16}{2} = \frac{30}{2} = 15$.$v_{c2} = \frac{14-16}{2} = \frac{-2}{2} = -1$.</p><p>Скорость не может быть отрицательной, поэтому $v_c = 15$ км/ч. Это значение удовлетворяет условию $v_c &gt; 3$.</p><p><strong>Ответ:</strong> 15 км/ч.</p><p><strong>д)</strong> Пусть $v_1$ — скорость первого поезда (в км/ч), а $v_2$ — скорость второго поезда (в км/ч).</p><p>Из первого условия: время первого поезда для прохождения 180 км ($t_1 = \frac{180}{v_1}$) на 1,5 часа меньше времени второго ($t_2 = \frac{180}{v_2}$):$\frac{180}{v_2} - \frac{180}{v_1} = 1.5$.</p><p>Из второго условия: вместе за 3 часа поезда проезжают 162 км. Это означает, что сумма их скоростей, умноженная на 3, равна 162:$3(v_1 + v_2) = 162$.</p><p>Из второго уравнения находим сумму скоростей:$v_1 + v_2 = \frac{162}{3} = 54$.</p><p>Отсюда $v_1 = 54 - v_2$.</p><p>Подставим это выражение в первое уравнение:$\frac{180}{v_2} - \frac{180}{54 - v_2} = 1.5$.</p><p>Разделим уравнение на 1.5 (или умножим на 2/3):$\frac{120}{v_2} - \frac{120}{54 - v_2} = 1$.</p><p>Приведем к общему знаменателю $v_2(54-v_2)$:$120(54 - v_2) - 120v_2 = v_2(54 - v_2)$</p><p>$6480 - 120v_2 - 120v_2 = 54v_2 - v_2^2$</p><p>$6480 - 240v_2 = 54v_2 - v_2^2$</p><p>$v_2^2 - 294v_2 + 6480 = 0$.</p><p>Решим квадратное уравнение. Дискриминант $D = b^2 - 4ac = (-294)^2 - 4 \cdot 1 \cdot 6480 = 86436 - 25920 = 60516$.</p><p>$\sqrt{D} = \sqrt{60516} = 246$.</p><p>$v_2 = \frac{294 \pm 246}{2}$.</p><p>Получаем два корня для $v_2$:$v_{2_a} = \frac{294+246}{2} = \frac{540}{2} = 270$.$v_{2_b} = \frac{294-246}{2} = \frac{48}{2} = 24$.</p><p>Рассмотрим оба случая:1. Если $v_2 = 270$ км/ч, то $v_1 = 54 - 270 = -216$ км/ч. Скорость не может быть отрицательной, этот корень не подходит.2. Если $v_2 = 24$ км/ч, то $v_1 = 54 - 24 = 30$ км/ч. Оба значения положительны и являются решением.</p><p>Проверка: $t_1 = 180/30 = 6$ ч. $t_2 = 180/24 = 7.5$ ч. $t_2 - t_1 = 7.5 - 6 = 1.5$ ч. Условие выполняется.</p><p><strong>Ответ:</strong> скорость первого поезда 30 км/ч, скорость второго поезда 24 км/ч.</p>"
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                      "refs" => "1098342"
                      "type" => "book_page"
                    ]
                  ]
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                  #classCastCache: []
                  #attributeCastCache: []
                  #dateFormat: null
                  #appends: []
                  #dispatchesEvents: []
                  #observables: []
                  #relations: []
                  #touches: []
                  +timestamps: true
                  +usesUniqueIds: false
                  #hidden: []
                  #visible: []
                  #fillable: []
                  #guarded: array:1 [
                    0 => "*"
                  ]
                }
                2 => App\Models\Task {#1202
                  #connection: "mysql"
                  #table: "tasks"
                  #primaryKey: "id"
                  #keyType: "int"
                  +incrementing: true
                  #with: []
                  #withCount: []
                  +preventsLazyLoading: false
                  #perPage: 15
                  +exists: true
                  +wasRecentlyCreated: false
                  #escapeWhenCastingToString: false
                  #attributes: array:24 [
                    "id" => 1113598
                    "created_at" => "2026-04-10 13:58:26"
                    "updated_at" => null
                    "field_page_start" => "5"
                    "field_page_end" => null
                    "field_url" => "/10-klass/algebra/abylkasymova-uchebnik/00-8"
                    "field_display_title" => "8"
                    "field_outside_task" => null
                    "field_task_type" => Illuminate\Database\Eloquent\Collection {#1199
                      #items: array:1 [
                        0 => App\Models\Term {#1036}
                      ]
                      #escapeWhenCastingToString: false
                    }
                    "field_metatags_title" => null
                    "field_metatags_description" => null
                    "field_h1" => null
                    "field_description_top" => null
                    "field_description_bottom" => null
                    "field_match" => null
                    "breadcrumbs" => []
                    "edition_groups" => Illuminate\Database\Eloquent\Collection {#1217
                      #items: []
                      #escapeWhenCastingToString: false
                    }
                    "top_parent_branch" => Illuminate\Database\Eloquent\Collection {#1219
                      #items: array:1 [
                        0 => App\Models\Branch {#1045}
                      ]
                      #escapeWhenCastingToString: false
                    }
                    "parent_branches" => Illuminate\Database\Eloquent\Collection {#1215
                      #items: array:1 [
                        0 => App\Models\Branch {#1045}
                      ]
                      #escapeWhenCastingToString: false
                    }
                    "content" => Illuminate\Database\Eloquent\Collection {#1214
                      #items: array:3 [
                        0 => App\Models\Element {#1235 …30}
                        1 => App\Models\Element {#1237 …30}
                        2 => App\Models\Element {#1239 …30}
                      ]
                      #escapeWhenCastingToString: false
                    }
                    "next" => array:2 [
                      "refs" => "1113599"
                      "type" => "task"
                    ]
                    "previous" => array:2 [
                      "refs" => "1113597"
                      "type" => "task"
                    ]
                    "book" => Illuminate\Database\Eloquent\Collection {#1232
                      #items: array:1 [
                        0 => App\Models\Book {#1048}
                      ]
                      #escapeWhenCastingToString: false
                    }
                    "page" => array:2 [
                      "refs" => "1098342"
                      "type" => "book_page"
                    ]
                  ]
                  #original: array:24 [
                    "id" => 1113598
                    "created_at" => "2026-04-10 13:58:26"
                    "updated_at" => null
                    "field_page_start" => "5"
                    "field_page_end" => null
                    "field_url" => "/10-klass/algebra/abylkasymova-uchebnik/00-8"
                    "field_display_title" => "8"
                    "field_outside_task" => null
                    "field_task_type" => Illuminate\Database\Eloquent\Collection {#1199}
                    "field_metatags_title" => null
                    "field_metatags_description" => null
                    "field_h1" => null
                    "field_description_top" => null
                    "field_description_bottom" => null
                    "field_match" => null
                    "breadcrumbs" => []
                    "edition_groups" => Illuminate\Database\Eloquent\Collection {#1217}
                    "top_parent_branch" => Illuminate\Database\Eloquent\Collection {#1219}
                    "parent_branches" => Illuminate\Database\Eloquent\Collection {#1215}
                    "content" => Illuminate\Database\Eloquent\Collection {#1214}
                    "next" => array:2 [
                      "refs" => "1113599"
                      "type" => "task"
                    ]
                    "previous" => array:2 [
                      "refs" => "1113597"
                      "type" => "task"
                    ]
                    "book" => Illuminate\Database\Eloquent\Collection {#1232}
                    "page" => array:2 [
                      "refs" => "1098342"
                      "type" => "book_page"
                    ]
                  ]
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                  #attributeCastCache: []
                  #dateFormat: null
                  #appends: []
                  #dispatchesEvents: []
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                  #touches: []
                  +timestamps: true
                  +usesUniqueIds: false
                  #hidden: []
                  #visible: []
                  #fillable: []
                  #guarded: array:1 [
                    0 => "*"
                  ]
                }
                3 => App\Models\Task {#1216
                  #connection: "mysql"
                  #table: "tasks"
                  #primaryKey: "id"
                  #keyType: "int"
                  +incrementing: true
                  #with: []
                  #withCount: []
                  +preventsLazyLoading: false
                  #perPage: 15
                  +exists: true
                  +wasRecentlyCreated: false
                  #escapeWhenCastingToString: false
                  #attributes: array:24 [
                    "id" => 1113599
                    "created_at" => "2026-04-10 13:58:26"
                    "updated_at" => null
                    "field_page_start" => "5"
                    "field_page_end" => null
                    "field_url" => "/10-klass/algebra/abylkasymova-uchebnik/00-9"
                    "field_display_title" => "9"
                    "field_outside_task" => null
                    "field_task_type" => Illuminate\Database\Eloquent\Collection {#1213
                      #items: array:1 [
                        0 => App\Models\Term {#1036}
                      ]
                      #escapeWhenCastingToString: false
                    }
                    "field_metatags_title" => null
                    "field_metatags_description" => null
                    "field_h1" => null
                    "field_description_top" => null
                    "field_description_bottom" => null
                    "field_match" => null
                    "breadcrumbs" => []
                    "edition_groups" => Illuminate\Database\Eloquent\Collection {#1231
                      #items: []
                      #escapeWhenCastingToString: false
                    }
                    "top_parent_branch" => Illuminate\Database\Eloquent\Collection {#1233
                      #items: array:1 [
                        0 => App\Models\Branch {#1045}
                      ]
                      #escapeWhenCastingToString: false
                    }
                    "parent_branches" => Illuminate\Database\Eloquent\Collection {#1229
                      #items: array:1 [
                        0 => App\Models\Branch {#1045}
                      ]
                      #escapeWhenCastingToString: false
                    }
                    "content" => Illuminate\Database\Eloquent\Collection {#1228
                      #items: array:3 [
                        0 => App\Models\Element {#1249 …30}
                        1 => App\Models\Element {#1251 …30}
                        2 => App\Models\Element {#1253 …30}
                      ]
                      #escapeWhenCastingToString: false
                    }
                    "next" => array:2 [
                      "refs" => "1113600"
                      "type" => "task"
                    ]
                    "previous" => array:2 [
                      "refs" => "1113598"
                      "type" => "task"
                    ]
                    "book" => Illuminate\Database\Eloquent\Collection {#1246
                      #items: array:1 [
                        0 => App\Models\Book {#1048}
                      ]
                      #escapeWhenCastingToString: false
                    }
                    "page" => array:2 [
                      "refs" => "1098342"
                      "type" => "book_page"
                    ]
                  ]
                  #original: array:24 [
                    "id" => 1113599
                    "created_at" => "2026-04-10 13:58:26"
                    "updated_at" => null
                    "field_page_start" => "5"
                    "field_page_end" => null
                    "field_url" => "/10-klass/algebra/abylkasymova-uchebnik/00-9"
                    "field_display_title" => "9"
                    "field_outside_task" => null
                    "field_task_type" => Illuminate\Database\Eloquent\Collection {#1213}
                    "field_metatags_title" => null
                    "field_metatags_description" => null
                    "field_h1" => null
                    "field_description_top" => null
                    "field_description_bottom" => null
                    "field_match" => null
                    "breadcrumbs" => []
                    "edition_groups" => Illuminate\Database\Eloquent\Collection {#1231}
                    "top_parent_branch" => Illuminate\Database\Eloquent\Collection {#1233}
                    "parent_branches" => Illuminate\Database\Eloquent\Collection {#1229}
                    "content" => Illuminate\Database\Eloquent\Collection {#1228}
                    "next" => array:2 [
                      "refs" => "1113600"
                      "type" => "task"
                    ]
                    "previous" => array:2 [
                      "refs" => "1113598"
                      "type" => "task"
                    ]
                    "book" => Illuminate\Database\Eloquent\Collection {#1246}
                    "page" => array:2 [
                      "refs" => "1098342"
                      "type" => "book_page"
                    ]
                  ]
                  #changes: []
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                  #attributeCastCache: []
                  #dateFormat: null
                  #appends: []
                  #dispatchesEvents: []
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                  #relations: []
                  #touches: []
                  +timestamps: true
                  +usesUniqueIds: false
                  #hidden: []
                  #visible: []
                  #fillable: []
                  #guarded: array:1 [
                    0 => "*"
                  ]
                }
                4 => App\Models\Task {#1230
                  #connection: "mysql"
                  #table: "tasks"
                  #primaryKey: "id"
                  #keyType: "int"
                  +incrementing: true
                  #with: []
                  #withCount: []
                  +preventsLazyLoading: false
                  #perPage: 15
                  +exists: true
                  +wasRecentlyCreated: false
                  #escapeWhenCastingToString: false
                  #attributes: array:24 [
                    "id" => 1113600
                    "created_at" => "2026-04-10 13:58:26"
                    "updated_at" => null
                    "field_page_start" => "5"
                    "field_page_end" => null
                    "field_url" => "/10-klass/algebra/abylkasymova-uchebnik/00-10"
                    "field_display_title" => "10"
                    "field_outside_task" => null
                    "field_task_type" => Illuminate\Database\Eloquent\Collection {#1227
                      #items: array:1 [
                        0 => App\Models\Term {#1036}
                      ]
                      #escapeWhenCastingToString: false
                    }
                    "field_metatags_title" => null
                    "field_metatags_description" => null
                    "field_h1" => null
                    "field_description_top" => null
                    "field_description_bottom" => null
                    "field_match" => null
                    "breadcrumbs" => []
                    "edition_groups" => Illuminate\Database\Eloquent\Collection {#1245
                      #items: []
                      #escapeWhenCastingToString: false
                    }
                    "top_parent_branch" => Illuminate\Database\Eloquent\Collection {#1247
                      #items: array:1 [
                        0 => App\Models\Branch {#1045}
                      ]
                      #escapeWhenCastingToString: false
                    }
                    "parent_branches" => Illuminate\Database\Eloquent\Collection {#1243
                      #items: array:1 [
                        0 => App\Models\Branch {#1045}
                      ]
                      #escapeWhenCastingToString: false
                    }
                    "content" => Illuminate\Database\Eloquent\Collection {#1242
                      #items: array:3 [
                        0 => App\Models\Element {#1263 …30}
                        1 => App\Models\Element {#1265 …30}
                        2 => App\Models\Element {#1267 …30}
                      ]
                      #escapeWhenCastingToString: false
                    }
                    "next" => array:2 [
                      "refs" => "1113601"
                      "type" => "task"
                    ]
                    "previous" => array:2 [
                      "refs" => "1113599"
                      "type" => "task"
                    ]
                    "book" => Illuminate\Database\Eloquent\Collection {#1260
                      #items: array:1 [
                        0 => App\Models\Book {#1048}
                      ]
                      #escapeWhenCastingToString: false
                    }
                    "page" => array:2 [
                      "refs" => "1098342"
                      "type" => "book_page"
                    ]
                  ]
                  #original: array:24 [
                    "id" => 1113600
                    "created_at" => "2026-04-10 13:58:26"
                    "updated_at" => null
                    "field_page_start" => "5"
                    "field_page_end" => null
                    "field_url" => "/10-klass/algebra/abylkasymova-uchebnik/00-10"
                    "field_display_title" => "10"
                    "field_outside_task" => null
                    "field_task_type" => Illuminate\Database\Eloquent\Collection {#1227}
                    "field_metatags_title" => null
                    "field_metatags_description" => null
                    "field_h1" => null
                    "field_description_top" => null
                    "field_description_bottom" => null
                    "field_match" => null
                    "breadcrumbs" => []
                    "edition_groups" => Illuminate\Database\Eloquent\Collection {#1245}
                    "top_parent_branch" => Illuminate\Database\Eloquent\Collection {#1247}
                    "parent_branches" => Illuminate\Database\Eloquent\Collection {#1243}
                    "content" => Illuminate\Database\Eloquent\Collection {#1242}
                    "next" => array:2 [
                      "refs" => "1113601"
                      "type" => "task"
                    ]
                    "previous" => array:2 [
                      "refs" => "1113599"
                      "type" => "task"
                    ]
                    "book" => Illuminate\Database\Eloquent\Collection {#1260}
                    "page" => array:2 [
                      "refs" => "1098342"
                      "type" => "book_page"
                    ]
                  ]
                  #changes: []
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                  #classCastCache: []
                  #attributeCastCache: []
                  #dateFormat: null
                  #appends: []
                  #dispatchesEvents: []
                  #observables: []
                  #relations: []
                  #touches: []
                  +timestamps: true
                  +usesUniqueIds: false
                  #hidden: []
                  #visible: []
                  #fillable: []
                  #guarded: array:1 [
                    0 => "*"
                  ]
                }
                5 => App\Models\Task {#1244
                  #connection: "mysql"
                  #table: "tasks"
                  #primaryKey: "id"
                  #keyType: "int"
                  +incrementing: true
                  #with: []
                  #withCount: []
                  +preventsLazyLoading: false
                  #perPage: 15
                  +exists: true
                  +wasRecentlyCreated: false
                  #escapeWhenCastingToString: false
                  #attributes: array:24 [
                    "id" => 1113601
                    "created_at" => "2026-04-10 13:58:26"
                    "updated_at" => null
                    "field_page_start" => "5"
                    "field_page_end" => null
                    "field_url" => "/10-klass/algebra/abylkasymova-uchebnik/00-11"
                    "field_display_title" => "11"
                    "field_outside_task" => null
                    "field_task_type" => Illuminate\Database\Eloquent\Collection {#1241
                      #items: array:1 [
                        0 => App\Models\Term {#1036}
                      ]
                      #escapeWhenCastingToString: false
                    }
                    "field_metatags_title" => null
                    "field_metatags_description" => null
                    "field_h1" => null
                    "field_description_top" => null
                    "field_description_bottom" => null
                    "field_match" => null
                    "breadcrumbs" => []
                    "edition_groups" => Illuminate\Database\Eloquent\Collection {#1259
                      #items: []
                      #escapeWhenCastingToString: false
                    }
                    "top_parent_branch" => Illuminate\Database\Eloquent\Collection {#1261
                      #items: array:1 [
                        0 => App\Models\Branch {#1045}
                      ]
                      #escapeWhenCastingToString: false
                    }
                    "parent_branches" => Illuminate\Database\Eloquent\Collection {#1257
                      #items: array:1 [
                        0 => App\Models\Branch {#1045}
                      ]
                      #escapeWhenCastingToString: false
                    }
                    "content" => Illuminate\Database\Eloquent\Collection {#1256
                      #items: array:3 [
                        0 => App\Models\Element {#1277 …30}
                        1 => App\Models\Element {#1279 …30}
                        2 => App\Models\Element {#1281 …30}
                      ]
                      #escapeWhenCastingToString: false
                    }
                    "next" => array:2 [
                      "refs" => "1113602"
                      "type" => "task"
                    ]
                    "previous" => array:2 [
                      "refs" => "1113600"
                      "type" => "task"
                    ]
                    "book" => Illuminate\Database\Eloquent\Collection {#1274
                      #items: array:1 [
                        0 => App\Models\Book {#1048}
                      ]
                      #escapeWhenCastingToString: false
                    }
                    "page" => array:2 [
                      "refs" => "1098342"
                      "type" => "book_page"
                    ]
                  ]
                  #original: array:24 [
                    "id" => 1113601
                    "created_at" => "2026-04-10 13:58:26"
                    "updated_at" => null
                    "field_page_start" => "5"
                    "field_page_end" => null
                    "field_url" => "/10-klass/algebra/abylkasymova-uchebnik/00-11"
                    "field_display_title" => "11"
                    "field_outside_task" => null
                    "field_task_type" => Illuminate\Database\Eloquent\Collection {#1241}
                    "field_metatags_title" => null
                    "field_metatags_description" => null
                    "field_h1" => null
                    "field_description_top" => null
                    "field_description_bottom" => null
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                    "breadcrumbs" => []
                    "edition_groups" => Illuminate\Database\Eloquent\Collection {#1259}
                    "top_parent_branch" => Illuminate\Database\Eloquent\Collection {#1261}
                    "parent_branches" => Illuminate\Database\Eloquent\Collection {#1257}
                    "content" => Illuminate\Database\Eloquent\Collection {#1256}
                    "next" => array:2 [
                      "refs" => "1113602"
                      "type" => "task"
                    ]
                    "previous" => array:2 [
                      "refs" => "1113600"
                      "type" => "task"
                    ]
                    "book" => Illuminate\Database\Eloquent\Collection {#1274}
                    "page" => array:2 [
                      "refs" => "1098342"
                      "type" => "book_page"
                    ]
                  ]
                  #changes: []
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                  #attributeCastCache: []
                  #dateFormat: null
                  #appends: []
                  #dispatchesEvents: []
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                  #relations: []
                  #touches: []
                  +timestamps: true
                  +usesUniqueIds: false
                  #hidden: []
                  #visible: []
                  #fillable: []
                  #guarded: array:1 [
                    0 => "*"
                  ]
                }
                6 => App\Models\Task {#1258
                  #connection: "mysql"
                  #table: "tasks"
                  #primaryKey: "id"
                  #keyType: "int"
                  +incrementing: true
                  #with: []
                  #withCount: []
                  +preventsLazyLoading: false
                  #perPage: 15
                  +exists: true
                  +wasRecentlyCreated: false
                  #escapeWhenCastingToString: false
                  #attributes: array:24 [
                    "id" => 1113602
                    "created_at" => "2026-04-10 13:58:26"
                    "updated_at" => null
                    "field_page_start" => "5"
                    "field_page_end" => null
                    "field_url" => "/10-klass/algebra/abylkasymova-uchebnik/00-12"
                    "field_display_title" => "12"
                    "field_outside_task" => null
                    "field_task_type" => Illuminate\Database\Eloquent\Collection {#1255
                      #items: array:1 [
                        0 => App\Models\Term {#1036}
                      ]
                      #escapeWhenCastingToString: false
                    }
                    "field_metatags_title" => null
                    "field_metatags_description" => null
                    "field_h1" => null
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                    "breadcrumbs" => []
                    "edition_groups" => Illuminate\Database\Eloquent\Collection {#1273
                      #items: []
                      #escapeWhenCastingToString: false
                    }
                    "top_parent_branch" => Illuminate\Database\Eloquent\Collection {#1275
                      #items: array:1 [
                        0 => App\Models\Branch {#1045}
                      ]
                      #escapeWhenCastingToString: false
                    }
                    "parent_branches" => Illuminate\Database\Eloquent\Collection {#1271
                      #items: array:1 [
                        0 => App\Models\Branch {#1045}
                      ]
                      #escapeWhenCastingToString: false
                    }
                    "content" => Illuminate\Database\Eloquent\Collection {#1270
                      #items: array:3 [
                        0 => App\Models\Element {#1291 …30}
                        1 => App\Models\Element {#1293 …30}
                        2 => App\Models\Element {#1295 …30}
                      ]
                      #escapeWhenCastingToString: false
                    }
                    "next" => array:2 [
                      "refs" => "1113603"
                      "type" => "task"
                    ]
                    "previous" => array:2 [
                      "refs" => "1113601"
                      "type" => "task"
                    ]
                    "book" => Illuminate\Database\Eloquent\Collection {#1288
                      #items: array:1 [
                        0 => App\Models\Book {#1048}
                      ]
                      #escapeWhenCastingToString: false
                    }
                    "page" => array:2 [
                      "refs" => "1098342"
                      "type" => "book_page"
                    ]
                  ]
                  #original: array:24 [
                    "id" => 1113602
                    "created_at" => "2026-04-10 13:58:26"
                    "updated_at" => null
                    "field_page_start" => "5"
                    "field_page_end" => null
                    "field_url" => "/10-klass/algebra/abylkasymova-uchebnik/00-12"
                    "field_display_title" => "12"
                    "field_outside_task" => null
                    "field_task_type" => Illuminate\Database\Eloquent\Collection {#1255}
                    "field_metatags_title" => null
                    "field_metatags_description" => null
                    "field_h1" => null
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                    "breadcrumbs" => []
                    "edition_groups" => Illuminate\Database\Eloquent\Collection {#1273}
                    "top_parent_branch" => Illuminate\Database\Eloquent\Collection {#1275}
                    "parent_branches" => Illuminate\Database\Eloquent\Collection {#1271}
                    "content" => Illuminate\Database\Eloquent\Collection {#1270}
                    "next" => array:2 [
                      "refs" => "1113603"
                      "type" => "task"
                    ]
                    "previous" => array:2 [
                      "refs" => "1113601"
                      "type" => "task"
                    ]
                    "book" => Illuminate\Database\Eloquent\Collection {#1288}
                    "page" => array:2 [
                      "refs" => "1098342"
                      "type" => "book_page"
                    ]
                  ]
                  #changes: []
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                  #classCastCache: []
                  #attributeCastCache: []
                  #dateFormat: null
                  #appends: []
                  #dispatchesEvents: []
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                  #relations: []
                  #touches: []
                  +timestamps: true
                  +usesUniqueIds: false
                  #hidden: []
                  #visible: []
                  #fillable: []
                  #guarded: array:1 [
                    0 => "*"
                  ]
                }
                7 => App\Models\Task {#1272
                  #connection: "mysql"
                  #table: "tasks"
                  #primaryKey: "id"
                  #keyType: "int"
                  +incrementing: true
                  #with: []
                  #withCount: []
                  +preventsLazyLoading: false
                  #perPage: 15
                  +exists: true
                  +wasRecentlyCreated: false
                  #escapeWhenCastingToString: false
                  #attributes: array:24 [
                    "id" => 1113603
                    "created_at" => "2026-04-10 13:58:26"
                    "updated_at" => null
                    "field_page_start" => "5"
                    "field_page_end" => "6"
                    "field_url" => "/10-klass/algebra/abylkasymova-uchebnik/00-13"
                    "field_display_title" => "13"
                    "field_outside_task" => "0"
                    "field_task_type" => Illuminate\Database\Eloquent\Collection {#1269
                      #items: array:1 [
                        0 => App\Models\Term {#1036}
                      ]
                      #escapeWhenCastingToString: false
                    }
                    "field_metatags_title" => null
                    "field_metatags_description" => null
                    "field_h1" => null
                    "field_description_top" => null
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№13 (с. 5)
Условие. №13 (с. 5)
скриншот условия
Алгебра, 10 класс Учебник, авторы: Абылкасымова Алма Есимбековна, Жумагулова Зауре Абдыкеновна, издательство Мектеп, Алматы, 2019, страница 5, номер 13, Условие
Алгебра, 10 класс Учебник, авторы: Абылкасымова Алма Есимбековна, Жумагулова Зауре Абдыкеновна, издательство Мектеп, Алматы, 2019, страница 5, номер 13, Условие (продолжение 2)

13. а) Первое натуральное число составляет 75% от второго натурального числа. Найдите натуральные числа, если значение их произведений равно 1200;

б) если числитель дроби увеличить на 2, а знаменатель на 3, то получим дробь на $\frac{49}{35}$ больше данной дроби. Найдите первоначальную дробь;

в) значение суммы цифр двузначного числа равно 9, а значение разности квадратов его цифр равно 27. Найдите двузначное число;

г) катер проплыл по течению реки 36 км, против течения 48 км. На весь путь потрачено 6 ч времени. Найдите собственную скорость катера, если скорость течения реки равна 3 км/ч;

д) промежуток 180 км первый поезд проходит на 1,5 ч быстрее, чем второй поезд. Найдите скорость каждого поезда, если поезда вместе за 3 ч проезжают 162 км.

Решение. №13 (с. 5)
Алгебра, 10 класс Учебник, авторы: Абылкасымова Алма Есимбековна, Жумагулова Зауре Абдыкеновна, издательство Мектеп, Алматы, 2019, страница 5, номер 13, Решение
Алгебра, 10 класс Учебник, авторы: Абылкасымова Алма Есимбековна, Жумагулова Зауре Абдыкеновна, издательство Мектеп, Алматы, 2019, страница 5, номер 13, Решение (продолжение 2)
Решение 2. №13 (с. 5)

а) Пусть первое натуральное число равно $x$, а второе натуральное число равно $y$.

Из условия задачи известно, что первое число составляет 75% от второго, что можно записать в виде уравнения:$x = 0.75y$ или $x = \frac{3}{4}y$.

Также известно, что произведение этих чисел равно 1200:$x \cdot y = 1200$.

Подставим первое уравнение во второе:$(\frac{3}{4}y) \cdot y = 1200$

$\frac{3}{4}y^2 = 1200$

$y^2 = \frac{1200 \cdot 4}{3}$

$y^2 = 400 \cdot 4$

$y^2 = 1600$

Так как $y$ — натуральное число, $y = \sqrt{1600} = 40$.

Теперь найдем $x$, подставив значение $y$ в первое уравнение:$x = \frac{3}{4} \cdot 40 = 3 \cdot 10 = 30$.

Искомые натуральные числа — 30 и 40.Проверка: $30 \cdot 40 = 1200$. $30 / 40 = 0.75 = 75\%$.

Ответ: 30 и 40.

б) Пусть первоначальная дробь равна $\frac{x}{y}$.

Если числитель увеличить на 2, а знаменатель на 3, получим новую дробь $\frac{x+2}{y+3}$.

В условии сказано, что новая дробь на $\frac{49}{35}$ больше данной. Запишем уравнение:$\frac{x+2}{y+3} = \frac{x}{y} + \frac{49}{35}$.

Упростим дробь $\frac{49}{35} = \frac{7}{5}$.$\frac{x+2}{y+3} = \frac{x}{y} + \frac{7}{5}$.

Преобразуем уравнение:$\frac{x+2}{y+3} - \frac{x}{y} = \frac{7}{5}$

$\frac{y(x+2) - x(y+3)}{y(y+3)} = \frac{7}{5}$

$\frac{xy+2y-xy-3x}{y^2+3y} = \frac{7}{5}$

$\frac{2y-3x}{y^2+3y} = \frac{7}{5}$

$5(2y-3x) = 7(y^2+3y)$

$10y - 15x = 7y^2 + 21y$

$7y^2 + 11y + 15x = 0$

Для натуральных (положительных) чисел $x$ и $y$ сумма $7y^2 + 11y + 15x$ всегда будет положительной и не может равняться нулю. Это означает, что в условии задачи, скорее всего, опечатка. Наиболее вероятная опечатка — в значении $\frac{49}{35}$. Предположим, что имелось в виду $\frac{4}{35}$.

Тогда уравнение примет вид:$\frac{2y-3x}{y^2+3y} = \frac{4}{35}$

$35(2y-3x) = 4(y^2+3y)$

$70y - 105x = 4y^2 + 12y$

$105x = 58y - 4y^2$

$105x = 2y(29-2y)$

Поскольку $x$ и $y$ должны быть натуральными числами, $x > 0$, следовательно $29-2y > 0$, что означает $2y < 29$ или $y \le 14$.

Правая часть $2y(29-2y)$ должна быть делимой на 105, то есть на 3, 5 и 7.Проверим возможные значения $y$ от 1 до 14.Если $y=7$:$105x = 2 \cdot 7 \cdot (29 - 2 \cdot 7) = 14 \cdot (29 - 14) = 14 \cdot 15 = 210$.

$x = \frac{210}{105} = 2$.

Получили натуральные $x=2$ и $y=7$. Первоначальная дробь — $\frac{2}{7}$.

Проверка: новая дробь $\frac{2+2}{7+3} = \frac{4}{10} = \frac{2}{5}$. Разность $\frac{2}{5} - \frac{2}{7} = \frac{14-10}{35} = \frac{4}{35}$. Условие выполнено.

Ответ: $\frac{2}{7}$.

в) Пусть двузначное число состоит из цифры десятков $a$ и цифры единиц $b$. Значение числа равно $10a+b$.Из условия задачи имеем систему уравнений:1. Сумма цифр равна 9: $a+b=9$.2. Разность квадратов цифр равна 27: $a^2-b^2=27$. (Так как разность положительна, квадрат цифры десятков больше квадрата цифры единиц, $a > b$).

Разложим второе уравнение по формуле разности квадратов:$(a-b)(a+b)=27$.

Подставим в это уравнение значение $a+b$ из первого уравнения:$(a-b) \cdot 9 = 27$.

$a-b = \frac{27}{9} = 3$.

Теперь у нас есть простая система из двух линейных уравнений:$\begin{cases} a+b=9 \\ a-b=3 \end{cases}$

Сложим два уравнения:$(a+b)+(a-b) = 9+3$

$2a = 12$

$a = 6$.

Подставим значение $a$ в первое уравнение:$6+b=9$

$b=3$.

Цифра десятков равна 6, цифра единиц равна 3. Искомое число — 63.

Ответ: 63.

г) Пусть $v_c$ — собственная скорость катера в км/ч. Скорость течения реки $v_p = 3$ км/ч.

Скорость катера по течению: $v_{по} = v_c + v_p = v_c + 3$ км/ч.

Скорость катера против течения: $v_{против} = v_c - v_p = v_c - 3$ км/ч. (При этом $v_c > 3$).

Время движения по течению: $t_{по} = \frac{S_{по}}{v_{по}} = \frac{36}{v_c+3}$ ч.

Время движения против течения: $t_{против} = \frac{S_{против}}{v_{против}} = \frac{48}{v_c-3}$ ч.

Общее время в пути составляет 6 часов:$t_{по} + t_{против} = 6$

$\frac{36}{v_c+3} + \frac{48}{v_c-3} = 6$.

Разделим все уравнение на 6 для упрощения:$\frac{6}{v_c+3} + \frac{8}{v_c-3} = 1$.

Приведем к общему знаменателю $(v_c+3)(v_c-3)$:$6(v_c-3) + 8(v_c+3) = (v_c+3)(v_c-3)$

$6v_c - 18 + 8v_c + 24 = v_c^2 - 9$

$14v_c + 6 = v_c^2 - 9$

$v_c^2 - 14v_c - 15 = 0$.

Решим квадратное уравнение. Дискриминант $D = b^2 - 4ac = (-14)^2 - 4 \cdot 1 \cdot (-15) = 196 + 60 = 256$.

$v_c = \frac{-b \pm \sqrt{D}}{2a} = \frac{14 \pm \sqrt{256}}{2} = \frac{14 \pm 16}{2}$.

Получаем два корня:$v_{c1} = \frac{14+16}{2} = \frac{30}{2} = 15$.$v_{c2} = \frac{14-16}{2} = \frac{-2}{2} = -1$.

Скорость не может быть отрицательной, поэтому $v_c = 15$ км/ч. Это значение удовлетворяет условию $v_c > 3$.

Ответ: 15 км/ч.

д) Пусть $v_1$ — скорость первого поезда (в км/ч), а $v_2$ — скорость второго поезда (в км/ч).

Из первого условия: время первого поезда для прохождения 180 км ($t_1 = \frac{180}{v_1}$) на 1,5 часа меньше времени второго ($t_2 = \frac{180}{v_2}$):$\frac{180}{v_2} - \frac{180}{v_1} = 1.5$.

Из второго условия: вместе за 3 часа поезда проезжают 162 км. Это означает, что сумма их скоростей, умноженная на 3, равна 162:$3(v_1 + v_2) = 162$.

Из второго уравнения находим сумму скоростей:$v_1 + v_2 = \frac{162}{3} = 54$.

Отсюда $v_1 = 54 - v_2$.

Подставим это выражение в первое уравнение:$\frac{180}{v_2} - \frac{180}{54 - v_2} = 1.5$.

Разделим уравнение на 1.5 (или умножим на 2/3):$\frac{120}{v_2} - \frac{120}{54 - v_2} = 1$.

Приведем к общему знаменателю $v_2(54-v_2)$:$120(54 - v_2) - 120v_2 = v_2(54 - v_2)$

$6480 - 120v_2 - 120v_2 = 54v_2 - v_2^2$

$6480 - 240v_2 = 54v_2 - v_2^2$

$v_2^2 - 294v_2 + 6480 = 0$.

Решим квадратное уравнение. Дискриминант $D = b^2 - 4ac = (-294)^2 - 4 \cdot 1 \cdot 6480 = 86436 - 25920 = 60516$.

$\sqrt{D} = \sqrt{60516} = 246$.

$v_2 = \frac{294 \pm 246}{2}$.

Получаем два корня для $v_2$:$v_{2_a} = \frac{294+246}{2} = \frac{540}{2} = 270$.$v_{2_b} = \frac{294-246}{2} = \frac{48}{2} = 24$.

Рассмотрим оба случая:1. Если $v_2 = 270$ км/ч, то $v_1 = 54 - 270 = -216$ км/ч. Скорость не может быть отрицательной, этот корень не подходит.2. Если $v_2 = 24$ км/ч, то $v_1 = 54 - 24 = 30$ км/ч. Оба значения положительны и являются решением.

Проверка: $t_1 = 180/30 = 6$ ч. $t_2 = 180/24 = 7.5$ ч. $t_2 - t_1 = 7.5 - 6 = 1.5$ ч. Условие выполняется.

Ответ: скорость первого поезда 30 км/ч, скорость второго поезда 24 км/ч.

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